Key Upd | Lab Activity Blood Type Pedigree Mystery Answer

Once the parent genotypes are established, perform the cross to determine the probability of the Claimant’s blood type.

allele to a child. Therefore, Family Jones can never have a child with Type O blood ( ). Furthermore, because the father will contribute either IAcap I to the cap A-th power IBcap I to the cap B-th power , look at the potential for Type AB vs Type B.

: Often deduced as A+ or B+ based on his children's profiles . lab activity blood type pedigree mystery answer key upd

Baby 3 (Type B) belongs to Family Brown. If the mother passes her IBcap I to the cap B-th power allele and the father passes his recessive allele, the child will be IBicap I to the cap B-th power i Summary Master Matrix Mother's Genotype Father's Genotype Assigned Baby Baby's Genotype Smith Baby 1 (Type O) Jones IAicap I to the cap A-th power i IAIAcap I to the cap A-th power cap I to the cap A-th power IAIBcap I to the cap A-th power cap I to the cap B-th power Baby 2 (Type AB) IAIBcap I to the cap A-th power cap I to the cap B-th power Brown IBicap I to the cap B-th power i IAicap I to the cap A-th power i Baby 3 (Type B) IBicap I to the cap B-th power i

Answer:

If a child is Type O, both parents must carry at least one "i" allele.

The Jones family cannot biological parent a child with Type O ( ) or Type AB ( IAIBcap I to the cap A-th power cap I to the cap B-th power Matching Baby Y (AB-) Baby Y's Genotype: IAIBcap I to the cap A-th power cap I to the cap B-th power Once the parent genotypes are established, perform the

Pedigree analysis is a fundamental skill in genetics, allowing students to trace phenotypes and genotypes through multiple generations. Combining pedigree analysis with blood typing creates an engaging, real-world mystery that reinforces concepts of codominance, multiple alleles, and Mendelian inheritance.

So probability for an A− child = (25% for A) × (25% for −) = 6.25% per child under independent assortment. Furthermore, because the father will contribute either IAcap

Both follow simple Mendelian inheritance . Rh+ ( ) and Free earlobes ( ) are dominant; Rh- ( ) and Attached earlobes ( ) are recessive. 3. Solving the Mystery